A beaker contains 50% of wine second beaker contains 25% which has capacity twice as 1st one and remaining filled with water and these are poured into a third beaker what fraction of wine does 3rd beaker contain?

• assume
  first beaker capacity is 100 lit, so first beaker contains 50 lit of wine
  second beaker capacity is 200 lit,so 25%of 200 is 50 lit
  so in a mixture of 300 lit 100 lit is wine
  % of wine is 100/300=0.33
  0.33*100=33.33
  
• 11 years agoHelpfull: Yes(31) No(1)
• 33.33% of the wine first one contain like this (x/2,x/2) second one contains (x/2,3x/2) now the third one contains total 3x solution in that wine x/2+x/2=x then percentage x/3x*100=33.33%
• 10 years agoHelpfull: Yes(0) No(1)
• for the first beaker,
  capacity(let)=x
  wine=x/2
  water=x/2
  for the second beaker,
  wine=x/2
  water=3x/2
  for the third beaker=first beaker + second beaker
  =x+2x(water)
  wine%=x/3x*100
  =33.33%
• 8 years agoHelpfull: Yes(0) No(1)