Q. A cycled from P to Q at 10 kmph and returned at the rate of 9 kmph. B cycled both ways at 12 kmph. In the whole journey B took 10 minutes less than A. Find the distance between P and Q.

• A -time = d/10 + d/9 = 19d/90 hours
  B -time = 2d/12 = d/6 hours
  10 min = 1/6 hours
  Thus 19d/90 - d/6 = 1/6
  (19d-15d)/90 = 1/6
  4d/90 = 1/6
  thus d= 15/4 km = 3.75km
• 10 years agoHelpfull: Yes(41) No(4)
• LET X IS THE DISTANCE
  THEN
  X/9+X/10=X/12+X/12+10/60.
  AFTER CALCULATION
  X=3.75
• 10 years agoHelpfull: Yes(18) No(1)
• T = D/S
  Ta = (D/10 + D/9) = (19D/90) hrs
  Tb = (D/12 + D/12) = (D/6) hrs
  
  Tb = (Ta - 10 minutes)
  = (Ta - (1/6)hours)
  => D/6 = (19D/90) - (1/6)
  => 1/6 = (19D-15D)/90
  => 15 = 4D
  => D = 3.75 km
• 10 years agoHelpfull: Yes(5) No(1)
• 32.5
  
  let the distance x km.
  A cycled p to q then time = x/10 min
  A cycled q to p then time = x/9 min
  Total time taken by A = (x/10+x/9)=19x/90 min
  Now B taken time to cycled from p to q and q to p is (x/12+x/12) =2x/12 = x/6.
  
  According question , B took 10 min less than A.
  then 19x/90 = x/6+10
  19x/90-x/6=10
  114x-90x=900
  then 24x=900
  x=32.5
• 10 years agoHelpfull: Yes(4) No(23)
• let the total distance is X+X=2X
  and B completes it in T hr
  den A will take T+1/6 hr
  now write the two equation for time taken
  for B 2X/12=T
  for A X/10+X/9= T+1/6
  now solve these two eqn
  we will get X/6=T or X=6T
  put it in equ for A
  u will get 6T/10+6T/9=T+1/6
  =>114T=90T+15
  =>24T=15
  =>T=15/24
  so X=6*15/24=3.75
• 10 years agoHelpfull: Yes(2) No(1)
• let distance b x
  A takes time t= x/10+x/9 = 19x/90
  B takes time t= 2*x/12= x/6
  difference= 19x/90-x/6 =10/60 =>x=3.75(ans)
• 10 years agoHelpfull: Yes(2) No(3)
• avg speed of a=(2*10*9/(10+9))==180/19
  avg speed of b=12
  b hr=a hr-(10/60) hr
  let distance be x.
  thus
  (x/12)=(19x/180)- (10/60)
  on solving we get total distance between P and Q
  i.e x=7.5
  now distance between p and q=(x/2)
  Therefore ans is 3.75
• 7 years agoHelpfull: Yes(2) No(0)
• A_ time=d/10 + d/9
  B_time= 2d/12 = d/6
  eq. is-
  d/10 + d/9 = d/6 +1/6 //10 min. = 1/6 hr //
  i.e. d= 3.75 km
• 10 years agoHelpfull: Yes(1) No(1)