jack started walking from 10:30am at speed of 6kmph and at 13:30 am paul follows him on a cycle with a speed of 8 kmph at what time will be jack 3km behind paul?

• midnight 12.
• 11 years agoHelpfull: Yes(27) No(3)
• answer will be
  time required ((6*3)+3)/(8-6)=10.5
  So answer is 24:00
• 11 years agoHelpfull: Yes(10) No(1)
• answer is 9:00pm
  bcs they will meet after 6 hr at 48km
  and now the relative speed is 2km/hr thus
  2km is covered in 60 minute then 3km can cover in????=90 minute
  thus total time is=6+1.30=7:30hr
  13:30+7:30=9:00pm or 21:00
• 11 years agoHelpfull: Yes(9) No(6)
• 9pm wiil be the answer...
• 11 years agoHelpfull: Yes(5) No(5)
• in 3 hrs distance covered by jack is 18km
  so eqtn will be: (18+6t)-8t=3 , so t=7.5 => ans=13.30+7.30=21:00.
• 11 years agoHelpfull: Yes(4) No(2)
• at midnight
• 11 years agoHelpfull: Yes(1) No(1)
• At 1330 jack will be ahead by 18 kms, and paul can overcome only 2kms per hour so it will take him 9 hours to reach to jack and get 3kms ahead he ll take 1.5 hrs more. so adding 10.5 hrs to existing. which will be 12 o clock in night.
  
  BDW there is no suck thing as 1330 am which you mentioned in the question
• 11 years agoHelpfull: Yes(1) No(1)
• 90+3/2=46.5
  13.30+46.5=12am
• 11 years agoHelpfull: Yes(1) No(0)
• the answer is at 24hrs
• 11 years agoHelpfull: Yes(0) No(2)
• the answer is 7 hrs and 30 min
• 11 years agoHelpfull: Yes(0) No(2)
• at 2400hrs
  
• 11 years agoHelpfull: Yes(0) No(2)
• after 9 hours they both travel 72km
  so at 10:30pm both are same
  at 12:00 the diff is 3 km..
  
• 11 years agoHelpfull: Yes(0) No(1)
• midnight 12
• 11 years agoHelpfull: Yes(0) No(0)
• answer is 19:30
  and now the relative speed is 2km/hr thus
  in 1.5 hrs jack will go=1.5*6=9km
  so time taken by paul to move ahead of jack by 3km=(9+3)/2=6hrs
  so the time will be=13:30+6:00=19:30
  
• 9 years agoHelpfull: Yes(0) No(0)