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Numerical Ability
Permutation and Combination
A drawer has 4 red hats and 4 blue hats.find the probability of getting excatly 3 blue hats when taking out 4 hats randomly out of the drawer and immediatly returning every hatto the drawer before taking out the next?
Read Solution (Total 9)
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- possible outcomes=(RRRR)(RRRB)(RRBR)(RBRR)(BRRR)(BBBR)(BBRB)(BRBB)(RBBB)(RRBB)(BBRR)(RBBR)(BRRB)(RBRB)(BRBR)(BBBB)
so toatl 16
n we want exactly 3 blue hats
so 4/16=1/4 ans. - 11 years agoHelpfull: Yes(25) No(5)
- It will be 1/2 * 1/2 * 1/2 * 1/2=1/16
- 11 years agoHelpfull: Yes(14) No(12)
- 4c3*4c1/8c4
- 11 years agoHelpfull: Yes(3) No(6)
- 4c1*4c1*4c1/(8c1*8c1*8c1)=1/16
- 11 years agoHelpfull: Yes(2) No(5)
- ans should be 1/8 as every time nos of hat in the drawer is 8 so the proabilty of taking out will be 4c3/8
- 11 years agoHelpfull: Yes(2) No(6)
- using binomial distribution
ans=4C3*(1/2)^3*1/2=1/4 - 11 years agoHelpfull: Yes(2) No(1)
- p(B^B^B)= P(B)*P(B)*P(B)
= (1/8)*(1/8)*(1/8)
- 11 years agoHelpfull: Yes(1) No(7)
- 4c1*4c1*4c1/(8c1*8c1*8c1)=1/16
- 11 years agoHelpfull: Yes(1) No(4)
- 3/4.1/4+1/4.3/4=3/8
- 11 years agoHelpfull: Yes(1) No(3)
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