Find the sum of number between 200 and 300, which is multiple of 3?

• n=33,a=201,l=297
  therefore s=n/2[2a+(n-1)d]
  =8217
• 11 years agoHelpfull: Yes(22) No(5)
• sn=34/2(201+300)=8517
• 11 years agoHelpfull: Yes(8) No(4)
• sorry guys
  wrong calculated
  sum of multiple of 3 between 200 and 300 first num is 201 and last num is 300
  as they are multiples we can take 3 as common
  so 3(67+68+69+70+........+99)
  as they are in a.p sum of them will be (n/2)[2a +(n -1)d]; here n is 33
  n=33
  a=67;d=1
  so 3(33/2)(2*67+((33-1)*1)=8715
• 11 years agoHelpfull: Yes(8) No(11)
• 8217 since number of terms is 33.
• 11 years agoHelpfull: Yes(6) No(6)
• i think ans is 175134
  sum of multiple of 3 between 200 and 300 first num is 201 and last num is 300
  as they are multiples we can take 3 as common
  so 3(67+68+69+70+........+100)
  as they are in a.p sum of them will be (n/2)[2a +(n -1)d]; here n is 34
  3(34/2)[2(67)+33(100)]=3*17(134+3300)=175134
• 11 years agoHelpfull: Yes(4) No(14)
• actually we have to find out the sum off 201+204+207+.....+300 this is in AP
  If the no of factors of 3 between 200 and 300 is n, then 300 = 201+(n-1)3 or, n =34. So the sum = (34/2)(201+300) = 8670.
• 11 years agoHelpfull: Yes(2) No(4)
• sum is 8217,n=33,a=201,l=297,d=3
• 11 years agoHelpfull: Yes(2) No(4)
• 201 to 300.a=201,n=3 tn=a+(n-1)d=>300=201+(n-1)3.n=34
  (34/2)(201+300)=8517
• 11 years agoHelpfull: Yes(1) No(3)
• sum is 8217,n=33,a=201,l=297,d=3
• 10 years agoHelpfull: Yes(1) No(0)
• ans is 168(204+300)/3
• 11 years agoHelpfull: Yes(0) No(5)
• sn=33/2(201+300)=8266
• 11 years agoHelpfull: Yes(0) No(6)
• sum in ap=n/2(2a+(n-1)d)
  n=34,a=201
  so sum=8517
• 11 years agoHelpfull: Yes(0) No(1)
• 8517 will be the correct answer !!!
• 11 years agoHelpfull: Yes(0) No(1)