counters marked 1,2,3 are placed in a bag and one of them is withdrawn and replaced.the operation being repeated three times,what is the chance of obtaining a total of 6 in these three operations.

• total(1,2,3)=n^r (repetition is allowed)
  =3^3=>27
  total=6
  =>(1+2+3)'s cases=3!=6
  =>(2+2+2)'s cases=1
  
  so,answer=(6+1)/27=7/27
• 11 years agoHelpfull: Yes(10) No(0)
• ans is 2/27
• 11 years agoHelpfull: Yes(0) No(5)