1. Sixteen men complete a work in 24 days while 48 children can do it in 16 days. Twelve men

started the work, after 14 days 12 children joined them. In how Many days will all of them together

complete the remaining work?

• answer is 12 days..
  work complete by 12 men in 14 days= 12*14/(24*16)
  Remaining work = 9/16
  work complete by 12 men & 12 children = (12/(24*16)) + 12/(48*16)
  no. of days = work complete by 12 men & 12 children / remaining work
  hence answer = 12days
• 11 years agoHelpfull: Yes(12) No(3)
• one day work of child and men =(1/(16*24)+1/(48*16))
  ans=12 days
• 11 years agoHelpfull: Yes(6) No(16)
• 1 man can do total work in 16*24=384 days, while a child can do total work in 48*16=768 days. So efficiencies are in ratio of M:C=2:1
  so 2 children = 1 man
  let work be eating 384 chocolates. so in 14 days 12*14*2=336 chocs are over. remaining=48 chocs. so let they work for x days together. 12*2choc per day*x+12*1 choc per day*x = 48
  x=1 day 8 hours
• 11 years agoHelpfull: Yes(5) No(4)
• 12 men 14days work = (12*14)/(24*16)=7/16
  therefore remaining work=1-7/16=9/16
  Now one day work of 1 man and 1 child=(12/(16*48)+12/(24*16))=3/64
  Hence,number of days requied is (9/16)/(3/64)=12 days
• 11 years agoHelpfull: Yes(4) No(0)
• Ans is 12 days
• 11 years agoHelpfull: Yes(3) No(8)
• 16men->24 days
  12men->18days(men is inversly proportional to time).
  48children->16days
  12children->4days
  initially 12 men started the work and they continue upto 14 days individually.
  after 14days 12children joined and they complete the work along with 12men.
  so all of them work together for 4 days
• 11 years agoHelpfull: Yes(2) No(14)
• 16M*24D = 48C*16D
  
  M=2C
  
  M/C = 2/1 -------- > (1)
  
  Equation (1) implies man can eat 2 choc/day meanwhile child can eat 1 choc/day.
  
  Therefore efficiencies would be 2:1
  
  According to the man days concept and equation (1) we can assume the total units of work done as
  
  16M*24D = 16*2choc/day*24 days=768 choc
  
  12 men have worked for 14 days=14 days*12*2 choc/day=336 choc
  
  Out of 768 choc,336 choc are already done.
  
  Rem work=768-336=432 choc
  
  This 432 chocolates work is done by 12 men and 12 children
  
  12 men can eat 12*2 choc/day=24 choc/day
  
  12 children can eat 12* 1 choc/day=12 choc/day
  
  Together 12M and 12C can eat 24choc/day+12choc/day=36choc/day
  
  So the remaining work of 432 choc can be eaten in 432choc/36 choc/day=12 days
• 5 years agoHelpfull: Yes(0) No(0)