Ram ordered for 6 black toys And some additional brown toys. The price of black toy is 2.5 times that of a brown toy. While preparing the bill, the clerk interchanged the number of black toys and brown toys which increased the bill by 45%. Find the number of brown toys.

• let cost of brown toy = x and black toy = 2.5x
  let y be no of brown toys
  (2.5*x*y + 6*x)-(6*2.5x+xy) = 45/100*(6*2.5x+xy)
  on solving y=15
• 10 years agoHelpfull: Yes(28) No(1)
• cost of black= bl, brown= br.
  bl=1.5br
  no. of black=6, brown= x
  6bl+x.br=cost=br(x+15)
  interchached= 6.br+x.bl=br(2.5x+6)
  profit=1.5x-9=45%
  x=15=n0. of brown toys
• 10 years agoHelpfull: Yes(8) No(0)
• no of brown toys is 15....
  15 is the right answer
  
• 10 years agoHelpfull: Yes(4) No(0)
• ans=15
  let x= no. of brown toys
  let p= price of one brown toy
  => actual price=6*2.5p+xp=A(let)...... eqn(1)
  bill prepared by clerk=x*2.5p+6p=A+0.45A ..... eqn(2)
  dividing above eqn 91) by (2)
  => x=15
  
• 10 years agoHelpfull: Yes(4) No(0)
• answer is 62
• 10 years agoHelpfull: Yes(1) No(12)
• i think ans is 8
• 10 years agoHelpfull: Yes(1) No(12)
• cost of black toy=2.5*brown
  so
  interchange blak, brown
  6*2.5=15
  let cost of brown toy=1 rs thn
  total no. of brown toys=15
  
• 9 years agoHelpfull: Yes(1) No(0)
• Let x and y be the cost of black and brown toys respectively.
  6x+by+(6x+by)*45/100=6y+bx
  20(6x+by)+9(6x+by)=20(6x+by)
  174x+29by=120y+20bx
  substitute x=2.5y
  435y+29by=120y+21by
  315y=21by
  b= 315/21 =15
• 9 years agoHelpfull: Yes(1) No(0)