A company's selection process is described below:
Applicant-1: Accepted
Applicant-2: Rejected
Applicant-3: Accepted
Applicant-4: Rejected
Applicant-5: Rejected
Applicant-6: Accepted
Applicant-7: Rejected
Applicant-8: Rejected
Applicant-9: Rejected
Applicant-10: Accepted

and so on

The company receives a total of N applicants and 5% of them are selected. Find the total no. of applications and total no. of selected candidates.

• 1/2,2/(1+2),3/(1+2+3),4/(1+2+3+4)..........n/(1+2+3+....n),now
  n/(1+2+3+4....n)*100=5 =2 n /n(n+1)*100 = 5.
  so answer is put n=39 u wud get ur answer;
• 11 years agoHelpfull: Yes(16) No(5)
• If 1 student got selected, then 1 rejected
  If 2 students got selected, then 1+2 rejected
  If 3 students got selected, then 1+2+3 rejected
  If 4 students got selected, then 1+2+3+4 rejected
  If n students got selected, then (1+2+3+4+...+n) rejected =n(n+1)/2 rejected
  
  For n students to be selected, total students appeared is = students who got accepted + students who got rejected = n+n(n+1)/2
  
  acceptance percentage, n/[n+n(n+1)/2]=5
  solving it for n, we got n=37
  Therefore accepted students are, n=37
  total students are, n+n(n+1)/2 = 37+37(37+1)/2 = 740
• 11 years agoHelpfull: Yes(10) No(0)
• n=37 is correct
  bcs accepted % till nth term ((n)/1+2+3....N+N)*100=5%
• 11 years agoHelpfull: Yes(6) No(1)
• gaurav can u xplain the logic clearly
• 11 years agoHelpfull: Yes(1) No(0)
• no of applicaition is N
  no of selected candidate is 0.05N
• 11 years agoHelpfull: Yes(0) No(3)
• plz explain
• 11 years agoHelpfull: Yes(0) No(0)
• mr.gaurav can u pls explain the logic clearly pls
  
• 11 years agoHelpfull: Yes(0) No(0)