f log 2 = 0. 3010, then find how many digits are contained in the number 256.

• answer is 17
• 13 years agoHelpfull: Yes(10) No(10)
• To find no. of digist in 256 (which is 3),
  Take log 256 and add 1 to the integer part and ignore the decimal part
  log 256 = log 28 = 8 log 2 = 8*0.301 = 2.408
  2.408+1 = 3.408
  Ignoring the decimal part, 3
  So, 256 has 3 digits, which is true
  
  Now, I guess we want to find out the no. of digits in 256
  So, answer = 1+log 256 = 1+56*log 2 =1+ 56*0.301 = 1+ 16.856
  1 + 16 = 17
  Hence, option 3
• 13 years agoHelpfull: Yes(10) No(5)
• Correct question is: If log 2 = 0. 3010, then find how many digits are contained in the number 256
  log256= 56 log2 = 56 * 0.3010 = 16.856
  256= Antilog 16.856
  Hence it will contain 17 numbers
• 11 years agoHelpfull: Yes(2) No(1)
• If log 2 = 0. 3010, then find how many digits are contained in the number 2^56.
  floor(56*log 2)+1=17
  
• 9 years agoHelpfull: Yes(1) No(0)