A group of twelve persons is to be seated around a circular table. There are only two women in the group find the probability that there is atleast three men between the two women.
(a)5/11
(b)7/12
(c)1/3
(d)2/9

• Actually it is 5/11. answer is correct.
• 11 years agoHelpfull: Yes(11) No(3)
• 511....
  btw two women there can be 3,4,5,6,7 men so 5c1 and total arrangements 10!
  (5c1*10!)11!
  11! bcz (n-1)!
• 11 years agoHelpfull: Yes(10) No(19)
• At least 3 men between two women means ,
  3 men between two women or 4 men between two women or 5 men between two women or 6 men bet 2 women or 7 m bet 2 w. or 8 m bet bet 2 w. 9 men bet 2 women or finally 10 men between two women.
  hence there are seven condition 7/12 is right ans.
• 11 years agoHelpfull: Yes(5) No(14)
• 5/11
  
  total 3m+2w=>5
  as it is a circular table it will be n-1
  given n=12
  therefore
  =(5)/(n-1)
  =5/(12-1)
  =5/11
• 11 years agoHelpfull: Yes(5) No(1)
• hi poorvi can u explain this
  
• 11 years agoHelpfull: Yes(0) No(1)
• ans is 7/12, 3 b/w 2,4 b/w 2,5 b/w 2,6 b/w 2, 7 b/w 2
  1-P(m>=3)=1-(5/12)=7/12
• 11 years agoHelpfull: Yes(0) No(1)
• 5/11 is correct answer
• 5 years agoHelpfull: Yes(0) No(1)
• Circular Table, between 2 female there should always be 3 or more than 3 males, So possible are:
  1) 3 males 2) 4 males 3) 5 males 4) 6 males 5) 7 males. Cannot be 8 males because then from other side only 2 males will be between females.
  So for all 5 cases, we can arrange 10 males in 10! ways. So total ways = 5 * 10!
  Total ways of arranging 12 people on circular table = (12-1)! = 11!
  So probability = 5*10! / 11! = 5/11
• 4 years agoHelpfull: Yes(0) No(0)