Speed of a train is 20km/hr . The strength of the steam was increased two-fold but due to
certain other factors, the friction also increased 1 ½ times. If in the beginning the ratio of the strength of steam and friction was 3:1 . Find the present speed of the train.
(a)40km/hr
(b)30km/hr
(c)45 km/hr
(d)None of these

• new ratio steam:friction is 6:1.5 as steam double and friction is 3/2 times so 6:1.5 =4:1, now as given 3:1=20 means 3x-x=20,x=10,s0 4:1 is 4x-x=30 ans is 30
• 11 years agoHelpfull: Yes(24) No(6)
• 45kmph is the answer
• 11 years agoHelpfull: Yes(8) No(8)
• Rate of steam - rate of friction=20;
  so, 3x-x=20; x=10
  IInd case: 6x-2.5 x= 45 Ans
• 11 years agoHelpfull: Yes(2) No(6)
• both concepts are right,,,please tell its final answer
• 11 years agoHelpfull: Yes(1) No(0)
• hw it is 45 ?
  
• 11 years agoHelpfull: Yes(0) No(0)