If a,b are two perfect square digits and ab is a two digit perfect square number,such that (axb)+(a+b)=ab then the value of [ba-(b+a)] is
(a)27
(b)81
(c)16
(d)None of these

• 81 is the solution.
  the number is 49...so a=4,b=9 which satisfies the relation
  (4*9)+4+9=49
  so the value (94-(9+4))=81
• 10 years agoHelpfull: Yes(54) No(1)
• if u take any two perfect square numbers lets 4 and 9 then
  4*9+(4+9)=49 this propoert holds ....so now to find ba we use 94 and then
  94-(9+4)=81 so ans is a
• 10 years agoHelpfull: Yes(7) No(0)
• 16,25,36,49,64,81 are 2 digit perfect squares
  49 satisfies the given condition (a*b)+(a+b)=ab
  so a=4,b=9
  [94-(9+4)]=81
• 10 years agoHelpfull: Yes(2) No(0)
• Bailore: how do you find the value of a=4 and b=9.. Please explain
• 10 years agoHelpfull: Yes(0) No(0)
• Its just an hit an trial method ,,it was an easy question thats why got 2^2 and 3^3 i.e{4 and 9 } as number
  
  number is 49 which satisfy all conditions
  
  and last [94-{9+4}]=81
• 10 years agoHelpfull: Yes(0) No(0)
• ans is :a=4,b=9
  4*9+4+9=49 is perfect square number...
  so ba-(b+a)=36-13=23
• 9 years agoHelpfull: Yes(0) No(0)
• a=1,b=9
  a=4,b=9
  Both will yield the same answer i.e 81
• 9 years agoHelpfull: Yes(0) No(1)