15 people sit round a circular table what are the odds against two particular people sitting together.
(a)7:1
(b)6:1
(c)5:1
(d)1:5

• ans is 6:1
  odds agianst an event=
  (possibilities of event not happenning)/(possibilities of event happening)
  =possibilities that 2 people are not togeather/possi that they are togeather
  = (14!-2*13!)/(2*13!)
  = 6:1
• 10 years agoHelpfull: Yes(70) No(1)
• @SUJITHA MADDULA
  in circular arrangement total no.of possiblities are (n-1)!
  her two particular people should sit together
  so we consider them as single person so total no.of people are 14
  and no.of arrangements possible are (14-1)! = 13!
  now the 2 people who are should be together can be arranged in 2 ways
  so total no.of possiblilities that they are together are 2*13!
• 10 years agoHelpfull: Yes(12) No(1)
• if n people are in circular fashion,the number of arrangements possible are
  (n-1)! but not n!.So,the possi that the two are togeather is (14-1)!*2! but not 14!*2!@LAXMI
• 10 years agoHelpfull: Yes(6) No(2)
• plz clear tis doubt @BAILORE...
  2 people are sitting together then possi for that they are together is 14!*2! then how 13!*2!....
  
• 10 years agoHelpfull: Yes(5) No(4)
• odds against an event=no of unfavorable choices/favourable choices
  ((14!-2*13!)/(2*13!))=6/1=6:1
• 10 years agoHelpfull: Yes(3) No(1)
• can u explain what is the 2*13! @bailore pradyumna acharya
• 10 years agoHelpfull: Yes(2) No(3)
• the all independent people can sit themselves in 14! ways in circular arrangement
  when 2 people sit together take as 1 unit the remaining 13+1 unit is arranged in 13 ways and 2 people among themselves 2! ways ratio of 1&2 we get 7:1
• 10 years agoHelpfull: Yes(1) No(1)
• ok..i understand the logic but can anybody explain me how (N-1)!number of ways are there for N people sitting in circular
• 10 years agoHelpfull: Yes(0) No(0)
• 7:1 because all people sit around a round table if any two particular people selected as sitting to gether remaining odds are only 7
  
• 8 years agoHelpfull: Yes(0) No(0)