14 men and 9 women complete a dam in 15 days 9 men and 4 women do the same in

let 1 man's 1 day's work=x and 1 woman's 1 day's work=y.
then, 14 men'n 1 day's work=14x and 9 women's 1 day's work=9y.
now,15 day's work of 14 men's and 9 women's=15(14x+9y).
since, 15(14x+9y)=1
or, 14x+9y=1/15......(1)
similarly,
9x+4y=1/40.......(2)
from {4 x eq(1)} - {9 x eq(2)}, we have
-25x=5/120
so, x=-5/(25x120)=-1/600.
substituting the value of x in eq(2), we have
y=1/100.
now, 10 men's and 10 women's work in 1 day's=10x(-1/600)+10x(1/100)
=10{1/100-1/600}=10{(6-1)/600}=(10x5)/600
=1/12
thus, 10 men and 10 women do one work in 12 day's.
11 years agoHelpfull: Yes(9) No(0)
from given data it is 14m+9w=15 and 9m+4w=40... so calculate their 1 day work
hence 1 day work of 14m+9w=1/15 and 9m+4w=1/40 solving that we get m's 1 day work = -1/600 and w= 1/100...so that implies 10w and 10w can do 50/600 in 1 day.. hence they will take 12 days
11 years agoHelpfull: Yes(4) No(0)
ans=12 days.
11 years agoHelpfull: Yes(2) No(0)
12 days?
11 years agoHelpfull: Yes(1) No(0)
by solving 14m+9w=1/15 and 9m+4w=1/40 we will get
m=-1/600 & w=1/100 by substituting in 10m+10w we get 1/12
so answer is 12 days
11 years agoHelpfull: Yes(1) No(0)
They can complete the job in 12 days.
11 years agoHelpfull: Yes(0) No(0)

14 men and 9 women complete a dam in 15 days. 9 men and 4 women do the same in 40 days. Determine the time for 10 men and 10 women to complete the same work?