In an airforce of a country, there are (3x^2-5x-2) fighter planes and (x^2-x-2) cargo planes. Both types of planes are put in different group in such a way that every group consists of equal number of planes. An official is appointed to take care of each and every group. Find out the least number of officials to be appointed so that there is atleast one official for every group.

• the above quadratic equations can be solve which will give the groups made and hence the officials required ...hence the ans is 2.
• 11 years agoHelpfull: Yes(12) No(3)
• do value putting... put x=1 or 2 or 3... we get a +ve solution for x=3..... which gives fighter =10 and cargo=4...thus 2 groups will be formed of 5 fighter and 2 cargo each..... :)
• 11 years agoHelpfull: Yes(10) No(2)
• (2)
  on solving for 'x', we get 2 fighter planes and 2 cargo planes. so total 2 groups are made..and hence 2 officials required.
• 11 years agoHelpfull: Yes(6) No(2)
• ans is 2 solve the quadratic eqnss.... we wil get
• 11 years agoHelpfull: Yes(1) No(0)
• planes are put in different groups ...means fighter and cargo planes cannot be in same group. also for x=1 and x=2 solution not feasible.for x=3 we get 10 fighter planes and 4 cargo planes. as each group contains equal no of planes and officials should be minimum so 2 groups of cargo planes with each group having 2 planes...and 5 groups of fighter planes each group with 2 planes.hence ANSWER is 5+2=7
• 11 years agoHelpfull: Yes(1) No(0)
• ans 2. 3x^2-5x-2=x^2-x-2
  i.e. x=2 so 2 planes from each type
• 11 years agoHelpfull: Yes(0) No(0)
• since x is common from both the equations so x==2 is the answer !!!
• 11 years agoHelpfull: Yes(0) No(0)
• minimum way you can divide a number containing equal values is 2..for example we can devide 8 as 4+4 or 22 as 11+11 so minimum nuber is 2,i.e 2 groups are required
• 10 years agoHelpfull: Yes(0) No(0)