In base 7,a number is written only using the digits 1,2,...,6. The number 21 in base 7 is equal to 2*7+1=15 in base 10.Similarly the number 135 in base 7 is 1x72+3x7+5 in base 10. What is the sum of base 7 numbers 1234 and 6543 in base 7.?

• 1234 in base 7= 466 in base 10.(4*7^0+3*7^1+2*7^2+1*7^3)
  6543 in base 7 =2334 in base 10.
  adding 466+2334=2800 in base 10.
  convert it into base 7 by dividing with 7.
  2800 in base 10 = 11110 in base 7.
  
• 11 years agoHelpfull: Yes(17) No(2)
• in base-7 the numbers will be 0,1,2,3,4,5,6 after 6 any number will be equal to 10 + (that number)%7(i.e base) for eg: 4 + 3 =7>6 therefore 10 + 7%7 = 10 + 0==>10
  now similarly 4 + 4 = 8>6 = 10 + 8%7 =10 + 1==>11
  now given problem
  4+3 = 10 carry =1
  1(c)+3+4 = 11 carry =1
  1(c)+2+5 = 11 carry =1
  1(c)+1+6 =11
  therefore answer = 11110
• 11 years agoHelpfull: Yes(7) No(0)
• 11110 is the sum in base 7
• 11 years agoHelpfull: Yes(2) No(1)
• directly add 1234 and 6543, in case of a resulting digit sum is 7, take carry 1 and put 0 in d place of the corresponding digit sum ..... and when ever digit sum is 8 take carry 1 and put 1 in d place of the corresponding digit sum...
  
  so the final answer is 11110
• 11 years agoHelpfull: Yes(2) No(0)
• please can u explain the procedure
• 11 years agoHelpfull: Yes(1) No(0)
• its easy just read basic number system
  
  ans is 11110
  
• 11 years agoHelpfull: Yes(1) No(0)