four parallel lines are drawn parallel to one side of an equilateral triangle such that it cuts the other two sides at equal intervals.the area of the largest segment thus formed is 27msqr.find the area of the triangle?

• Area of Trapezoid= ((a+b)*h))/2(where a and b are length of parallel sides)
  Now Since side is divided in 5 parts therefore,length of one interval=a/5
  Now use Sin60 and to calculate the height of trapezoid( ie. a root 3/10). and cos60 to calculate the base of the triangle whose hypotenuse is a/5..(i.e. will be a/10);
  We get b= a-(a/10+a/10)
  b= 4a/5
  now equate the area of trapezoid with 27..
  Hence area of equilateral triangle is 75 sqm
• 11 years agoHelpfull: Yes(28) No(5)
• the sides of equilateral triangle is divided into 5 equal parts. invert a copy of the triangle at the top to next segment. a total of 4 small equilateral triangles will be formed from th first 2 segments. repeat this for for the rest 3 segments, the last segment will have 9 such triangles.
  so 9x=27 =>x=3.
  total 25 such triangles will be formed so 75sqm
• 11 years agoHelpfull: Yes(19) No(3)
• let the side of equilateral triangle be 5x , since the sides are divided into 5 parts each of equal length.
  area of the whole triangle =( sqrt 3)/4 *(5x) ^2
  area of the triangle leaving the lower portion whoz value is given = ( sqrt 3)/4 *(4x) ^2
  diff of the two , i.e whole triangle -the triangle leaving the lower part = 27
  therefore ,
  ( sqrt 3)/4 *(5x) ^2- ( sqrt 3)/4 *(4x) ^2=27
  x^2= 12/ (sqrt 3)
  substitute in ( sqrt 3)/4 *(5x) which is area of whole triangle =75 m square
• 9 years agoHelpfull: Yes(10) No(1)
• monday.. coz peda is eaten following jalebi , and the days given are mon to fri..
• 8 years agoHelpfull: Yes(1) No(4)
• 102cm^2
  75+27=102,,,
  
• 11 years agoHelpfull: Yes(0) No(11)