TCS Company Numerical Ability Permutation and Combination

How many zeros will be there at the end of expression (2!)^2! + (4!)^4! + (8!)^8! + (9!)^9! + (10)^10! + (11!)^11!?

Read Solution (Total 11)

TCS Other Question

when numbers are written in base b,we have 12*25=333.the value of b is? Set A {1,3,10,17,19}, B{9,12,15,18,21} and set C{4,7,10,13,16,19} probability of "a num from A + a num from B > a num from C". (not sure about numbers)