A bag has 1,3,5,7,9,11 and 13 cm sticks .find the probablity that they they will form a triangle if 3 sticks are drawn?

• Ans is 13/35
  Total way of selecting=7C3=35
  Now selections that are in fever=(3,5,7),(3,7,9),(3,9,11),(3,11,13),(5,7,9),(5,7,11),(5,9,11),(5,9,13),(5,11,13),(7,9,11),(7,9,13),(7,11,13),(9,11,13)=total 13.
  Others are rejected because to form a triangle it is neccessary that the sum of 2 small sides must be greater than the third greatest side
• 11 years agoHelpfull: Yes(70) No(1)
• Total no of outcomes=7C3=35
  favourable cases=11{(3 5 7),(3 7 9),(3 9 11),(3 11 13),(5 7 9).....as sum of two sides of a triangle should be greater than or equal to third side}
  
  
  ans=11/35
• 11 years agoHelpfull: Yes(27) No(14)
• for triangle we req 3 sticks
  3/7
  
• 11 years agoHelpfull: Yes(2) No(13)
• Ans=13/35
  
• 11 years agoHelpfull: Yes(1) No(5)
• 7C3-8/7c3=27/35
  
  8 combinations are no possible...
  
  
  
  
  
• 11 years agoHelpfull: Yes(0) No(10)
• ans will be 173/210 there are 37 combinations which are not possible.
• 11 years agoHelpfull: Yes(0) No(6)
• there are 9 combinations in which the triangle set are not possible.
  these are with 5-9,5-11,5-13,7-9,7-11,7-13,9-11,9-13,11-13
  the probability is 7c3-9/7c3 i.e 35-9/35= 26/35
  
• 11 years agoHelpfull: Yes(0) No(1)