A and B finished a piece of work in 5 days. If A had worked at twice the speed and B at half the speed, they would have finished the work in four days. How many days would it have taken A to finish the work alone?

• 10 days
  5(x+y)=4(2x+y/2) thus x=y
  so a will take twice the time taken by a+b thus answer is 10 DAys
• 11 years agoHelpfull: Yes(10) No(0)
• 10 days is the answer
• 11 years agoHelpfull: Yes(6) No(1)
• x+y=5 (x and y no of days by A and B respectively)
  x/2 +2y=4 (as x increses its speed and hence decreases time same for B)
  ans x=4,y=1,
  
• 11 years agoHelpfull: Yes(5) No(4)
• Let the total wrk be 50units.A+B=5days A & B's one day work = 50/5*2 So per day each of them is 5 units.A works at twice speed so 10 units per day B does at half speed so 2.5 units per day. 10*4+2.5*4=50 So A alone can do the work in 10 days
• 11 years agoHelpfull: Yes(3) No(2)
• 10 days.... eqns formed will be a + b= (1/5) and 2a+(b/20=(1/4)
  where a and b are one day work for a and b respectively.
  solve it n u will get ans (1/10)
  i.e., 10 dayzz
• 11 years agoHelpfull: Yes(3) No(0)
• plzz explain it....
• 11 years agoHelpfull: Yes(1) No(0)
• (1/x+1/y)*5= (2/x+1/2y)*4 i.e x= y
  (1/x+1/x)*5= 1
  x= 10 days
• 11 years agoHelpfull: Yes(1) No(0)
• Since,SP is same for both items.
  Let the SP for both items be Rs.100
  Now for 25% profit using the formula
  ((SP-CP)/CP)*100=profit%,we get CP=Rs.80
  Similarly for 20% loss using the formula
  ((CP-SP)/CP)*100=loss%,we get CP=Rs.125
  now we can have total CP =Rs. 205 and SP=Rs200
  so loss 2.5%
  dummy question
• 11 years agoHelpfull: Yes(0) No(4)
• answer is 10 DAys
• 11 years agoHelpfull: Yes(0) No(0)