B takes 3 steps forward and 1 step backward while walking. He walks up a stationary escalator in 118 seconds. If it takes a total of 40 sec to reach the top when the escalator is moving, then find the speed of the escalator approximately.

• since first B moves 3 steps forward nd then 1 step backward so in total 4 seconds he moves only 2 steps forward so in 116 seconds he moves 58 steps forward now in next 2 seconds he moves 2 steps so in 118 seconds he moves total 60 steps forward.
  so no. of steps required to reach the top of the escalator is 60.
  now let d escalator moves a steps per second so in 4 seconds B moves 2 steps(3steps forward nd 1 step backward)in these 4 sec. escalator moves 4a step so in 4 sec. B moves a total of 2+4a step.
  so in 40 second total move=10*(2+4a)
  so, 10*(2+4a)=60
  hence a=1step/sec.
  
• 11 years agoHelpfull: Yes(28) No(6)
• Wrong or incomplete question
  
• 11 years agoHelpfull: Yes(5) No(2)
• pls any one explain it properly
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• 1 step/sec
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• 3.9 or 5.9
  
• 11 years agoHelpfull: Yes(2) No(2)
• dummy ques
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• 0.9 m/sec
  
• 11 years agoHelpfull: Yes(0) No(4)
• suppose it is taking 2 steps in 1 seconds so speed is 2m/s and time is 118 s so distance travelled by b is 118*2= 236
  now for for 40 sec it travels 80 m
  and speed = 80*40
  =3200
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• pls explain
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