what is the last two digit of (123)123!

• Answer is 00 because there is also present 5! and 2! this will give 00 so ans is 00.
• 11 years agoHelpfull: Yes(10) No(3)
• 123! will have more than 2 zeroes in the end hence it will be divisible by 4 .. so we can write is as (((23)^4)^k) .. where k = 123!/4.. now since 123 ! has more than 24 zeroes at the end 123!/4 will have last two digits as zeroes.. now 23^4 = 279841 we take 41 because only last two digits are needed... so question is converted into (41)^k = last digit will be 1 and second last will be 4*0=0 so last two digits 01
• 11 years agoHelpfull: Yes(5) No(4)
• 123, we have 1 * 2 * 3 * ....... * 123.. so many zero will come at last.. if u multiply with any you ll get same no of zero or extra zero's.. so the answer is 00
• 11 years agoHelpfull: Yes(4) No(4)
• 123! is in the power
  
• 11 years agoHelpfull: Yes(1) No(0)
• 123! will be having more than 2 zeros at the end and 123*..00=...00
  
  So 00 is the answer.
• 11 years agoHelpfull: Yes(0) No(2)
• answer is 124!-1. but 124! has more than 2 zero's
  now last two digit is (0000-01)=99
• 11 years agoHelpfull: Yes(0) No(1)
• 01 will be the answer !!!
• 11 years agoHelpfull: Yes(0) No(1)