How many integers N in the set of integers {1 , 2 , 3,.....100} are there such that N2 + N3 is a perfect square?
option
(1) 5
(2) 7
(3) 9
(4) 10

• 1
  4+5=9
  12+13=25
  24+25=49
  40+41=81
• 10 years agoHelpfull: Yes(20) No(5)
• 4= 3 + 1
  9 = 4 + 5
  16= 6 + 10
  25= 13 + 12
  36= 11 + 25
  49= 9 + 40
  64= 2 +62
  81= 7 + 74
  100= 8+ 92
  therefore answer= 9
• 10 years agoHelpfull: Yes(18) No(13)
• logic is how many perfect squares are there in 1 to 100 so it is 4,9,16,25,36,49,64,81,100
• 10 years agoHelpfull: Yes(5) No(3)
• answer is 7 because every odd square digit can be made by consecutive numbers.... check it.... hehehehe
• 10 years agoHelpfull: Yes(3) No(15)
• can you please elaborate... 16 can be obtained by 12+4,10+6 so there is so manyy pls elaborate
  
• 10 years agoHelpfull: Yes(2) No(0)
• ans is 7
  logic can be apply only on odd no.s which is a perfect square
  starting from 1 to 14(we have to go upto 199)
  we will get 7 odd no's
• 10 years agoHelpfull: Yes(1) No(2)
• ans will be 10 .... n2 +n3 = n2(n+1)... n2 is always a square of n ...so case is only (n+1)...so for n+1 to be square of any number ...values will be 1 ,3,8,15,24,35,48,63,80,99...so total values are 10....
• 8 years agoHelpfull: Yes(1) No(0)
• ans:9
  1+3=4
  4+5=9
  5+9=16
  16+9=25
  .
  .
  .100
  .
  24+25=49
  40+41=81
• 10 years agoHelpfull: Yes(0) No(2)
• 4+5=9,,12+13=25,,24+25=49,,+40+41=81,,60+61=121...ans5
• 9 years agoHelpfull: Yes(0) No(0)