Sum of the digits in the equation (16^100)*(125^135) is

• it can be also written as
  ((2^400)*(5^405))
  ((2^400)*(5^400)*(5^5))
  ((2*5)^400)*(5^5))
  ((10^400)*(5^5))
  as we know that 10^n= 10000......
  so ((1000....)*(3125))
  we get 312500000.....
  ans=3+1+2+5+0+0+0..... =11
  
  
  
• 11 years agoHelpfull: Yes(156) No(3)
• 2^400*5^405
  10^400*5^5
  10^4 has all digits 0 except one 1
  5^5 is 3125
  sum of digits is 12 i.e.1+3+1+2+5
• 11 years agoHelpfull: Yes(6) No(25)
• =16^100 * 125^135 => (2^4)^100 * (5^3)^135 => 2^400 * 5^405 = 2^400 * 5^400 * 5^5
  = (2*5)^400 *3125
  =10^400 * 3125
  
  sum of 10^400= 1+0 + 0+ 0+ ...... = 1
  sum of 3125 = 11
  
  therefore= 1 * 11 = 11
  
  therefore = 1 + 1= 2
  
  ans is 2
  
• 9 years agoHelpfull: Yes(3) No(1)
• 1+6+1+0+0+1++2+5+1+3+5=25
• 11 years agoHelpfull: Yes(1) No(9)
• Here options are 2 5 3 8. there is no 11 in the options
• 11 years agoHelpfull: Yes(1) No(0)
• 1+6=7*100=700
  1+2+5=8*135=1080
  so the sum is 1780
• 11 years agoHelpfull: Yes(0) No(34)
• (2^400)*5^405 =(10^400)*5^5
  3125*10^400 =four digits + 400 digits =totally 404 digits is the answer
• 11 years agoHelpfull: Yes(0) No(6)
• its 1+3+1+2+5=12 is the answer
• 11 years agoHelpfull: Yes(0) No(0)
• Sum of digits is 11. Ans.
• 11 years agoHelpfull: Yes(0) No(0)
• ans is 2
• 9 years agoHelpfull: Yes(0) No(1)
• 11 is the answer
  
• 9 years agoHelpfull: Yes(0) No(0)