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sum of consecutive odd numbers when divided by 10 gives a perfect square. One of the two digit number may be
option
a) 67
b) 31
c) 41
d) 93
Read Solution (Total 13)
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- its given sum of consecutive odd numbers. how many numbers we should add is not mentioned. odd numbers-1,3,5,7,9. to make sum divide by 10, 5 cant be used as 1+3+7+9 gives 0 at unit place.
so, 37+39+41+43=160 -> 16/10=16 (square of 4)
and also, 87+89+91+93=360 ->360/10=36 (square of 6)
hence both digits are valid. - 11 years agoHelpfull: Yes(22) No(4)
- e) none of these
- 11 years agoHelpfull: Yes(18) No(2)
- 41 ans
two odd no be=x-1
x+1
(x-1+x+1)/10=4(perfect sq)
x=40
one no is 39
2nd is 41 - 11 years agoHelpfull: Yes(14) No(28)
- 37+39+41=117
117/10 rem will be 17 this incorrect way.
31+33+35=99
99/10 rem will be 9 so 9 is a perfect sqrt. so 31 will be ans.
but in the given question not defind the how many odd no add. - 11 years agoHelpfull: Yes(6) No(3)
- 31+33=64=square(8)
- 11 years agoHelpfull: Yes(5) No(5)
- let us take x as odd number
so consecutive numbers be x,x+2,x+4,x+6,x+8,x+10,x+12,
x+14,x+16&x+18
sum of all consecutive numbers are (10x+80)/10=(x+8)=perfect square
take x=17 ;17+8=25(perfect square)
s0 x+14==17+14=31
ans=31
- 11 years agoHelpfull: Yes(3) No(0)
- its 41
37+39+41+43=160 - 11 years agoHelpfull: Yes(2) No(3)
- @Shubhashish gaurav ..........plzzz tell how many odd nos. should be added???
- 11 years agoHelpfull: Yes(1) No(0)
- 64 is ans
- 11 years agoHelpfull: Yes(0) No(2)
- here no. of odd cosecutive no.s are not mentioned
hence if we take 3 consecutive odd no.s then let it be:x-1,x+1,x+3.
(x-1+x+1+x+3)/10=9
3x+3=90
x=29
.'.ans shud be 28,30 n 32 which is wrong
so the answer should be none of these. - 11 years agoHelpfull: Yes(0) No(5)
- ansr is non of these.........
- 11 years agoHelpfull: Yes(0) No(0)
- my bad the correct ansr is 41.
as the nmber of consecutive numbers yo b added is not mentioned. - 11 years agoHelpfull: Yes(0) No(0)
- non of these
- 11 years agoHelpfull: Yes(0) No(0)
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