A beaker has 50% of wine and a second beaker contains 25% with capacity twice as 1st one and remainin filled with water and these are poured into third beaker.wat fraction of wine does 3rd beaker contain

• suppose 1st beaker holds 100 ltr;
  so wine =50 ltr;
  in 2 beaker, capacity: 200 ltr;
  wine:50 ltr water :150 ltr;
  total volume of wine : (50+50)/(100+200) :1/3
• 10 years agoHelpfull: Yes(59) No(2)
• wine in beaker capacity=1/2 volume of 1st=1
  wine in beaker capacity=(1/4)2=1/2 volume of 2nd=2
  total volume of both beaker=3
  total wine in new vilume=1/2+1/2=1
  fraction of wine does 3rd =1/3 ans
  
  
• 10 years agoHelpfull: Yes(5) No(1)
• let first beaker capacity = 100 ltr,
  i.e 50 ltr of wine in the beaker
  and second beaker 200 capacity
  50 ltr of wine and 150 ltr of water
  i.e total content = 50+200=250
  and total wine=100
  100/250=2/5
  
• 10 years agoHelpfull: Yes(3) No(9)
• 3/8 of the total capacity of third container is wine
  
• 10 years agoHelpfull: Yes(0) No(9)
• let vol of 1st be x then vol of 2nd beaker be 2x...
  50% of wine i.e x/2 of vol in 1st and that of in 2nd will be x/4.
  total vol of wine in 3rd beaker will be 3x/4 and that of water will be 5x/4.
  (3x-3x/4):(3x-0) i.e 4:3
• 10 years agoHelpfull: Yes(0) No(3)