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The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol, is:
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- 50% of 9ml = 30% of x ml. so, x= 15ml. now, amount of water to be added= 15-9= 6ml, as alcohol remains same.
- 13 years agoHelpfull: Yes(35) No(5)
- alcohol = 9*50/100 = 4.5 ml
30*x/100 = 4.5 ...... x = total amount of solution for which 4.5 ml forms 30% conc.
x = 15ml
thus water to be added = 15-9 = 6ml
- 13 years agoHelpfull: Yes(14) No(1)
- 50% of 9ml=30% of x ml
as the amt of of alcohol will remian the same.
hence the answer is 15ml - 13 years agoHelpfull: Yes(9) No(14)
- let is assume that the lotion has 50% alcohol and 50% water.
ratio = 1:1
alcohol=water=4.5ml
now if we want the quantity of alcohol- 30%
the quantity of water = 70%
the new ratio = 3:7
let x ml of water be added
we get : 4.5/4.5+x = 3/7
or x=6
hence 6ml of water is added. (ans) - 9 years agoHelpfull: Yes(3) No(0)
- 50% of 9ml =30% of xml
50/100*9=30/100*x
x=15
since it is reduced by 9ml we have,
15ml-9ml=6ml - 9 years agoHelpfull: Yes(3) No(0)
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