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Numerical Ability
Permutation and Combination
1. In how many rearrangements of the word ERASED, the letter 'A' is positioned in between the two 'E's ?
Read Solution (Total 19)
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- 4!=24 ans......
- 10 years agoHelpfull: Yes(22) No(6)
- case1:E _ _ _ _ E => 4!=24 (A can be any where in 3 blanks)
case 2:E _ _ _ E _ =>3*3!*2=36 (A can be in 3 blanks in b/w so can be arranged in 3 ways remaining 3 letters can be arranged by 3! and 2 ways of arranging E's)
case 3: E _ _ E _ _ =>2*3!*3=36
case 4: => E _ E _ _ _ => 4*3!=24
24+36+36+24=120 - 10 years agoHelpfull: Yes(16) No(21)
- they mentioned directly....that A must be between two 'E' s
So the word RSD(EAE) can be arranged in 4! ways =24
- 10 years agoHelpfull: Yes(9) No(2)
- it is 60.
E_ _ _ _E =4!*(2!/2!)[arranging 2 similar E]=24
E_ _ _E_ =3*3!*(2!/2!)=18
E_ _E_ _ =2*3!*(2!/2!)=12
E_E_ _ _ =1*3!*(2!/2!)=6
24+18+12+6=60 - 10 years agoHelpfull: Yes(5) No(7)
- @jayant the total no of combinations is 60
- 10 years agoHelpfull: Yes(4) No(4)
- as asked rearranged so guys don't include erased word in ur ans.
so answer is 120-1=119
120 is same as explain by jayant narwani. - 10 years agoHelpfull: Yes(3) No(1)
- consider 'EAE' a single letter.. then the no. of arrangements are = 4!
- 10 years agoHelpfull: Yes(2) No(2)
- we have to set as EAE ==3/2!(for repitition of 'E' 2 times)
then EAE RSD==4!
therefore (4*3*2*1)*(3/2)=36. - 10 years agoHelpfull: Yes(1) No(7)
- read the question carefully its A is b/w 2 E's not only A is b/w 2 E's
- 10 years agoHelpfull: Yes(1) No(0)
- for any rearrangement consider only the position of AAE
AAE,AEA,EAA
means one third of total no. having E in b/w two E's
hence , total arr.=6!/2!=360
ans=360/3=120 - 10 years agoHelpfull: Yes(1) No(3)
- yes pooja you are right ans is 60
- 10 years agoHelpfull: Yes(1) No(1)
- Two E‘s can be arranged in 1 way only(because Identical letters: [2!/2!])
then A can be arranged in between E‘s is oneway.
These (EAE) treated as one group(letter).
Remaining letters(RSD)& That group(letter) =4.
So Four Letters can be arranged in 4places can be done in 4! ways - 10 years agoHelpfull: Yes(1) No(1)
- we consider EAE as 1 then 6-3+1=5
so num of rearrangement= 5!= 120 - 10 years agoHelpfull: Yes(1) No(5)
- correct sol. is 120-1= 119
- 10 years agoHelpfull: Yes(0) No(2)
- result acc to me is 60 coz its clearly said that a should be between two e bt it is not said ki eae must be together....
- 10 years agoHelpfull: Yes(0) No(0)
- 3 vows. so (6-3+1)!=4!=24 ain middle. so vows can arrange only in 1 way.
so ans=24*1=24 - 10 years agoHelpfull: Yes(0) No(0)
- A is btwen e and e.rsd are one set eae are one set no ways 3(rsd)+1(eae)=4!=24
- 10 years agoHelpfull: Yes(0) No(0)
- 24
surbhi u r r8........ - 10 years agoHelpfull: Yes(0) No(0)
- None of these
- 3 years agoHelpfull: Yes(0) No(0)
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