TCS Company

In an equilateral triangle PQ, QR and RS are the sides with 5, 6 and 3 points on the sides respectively, find the maximum number of triangles that can be formed with these points..

Read Solution (Total 8)

totally there are 14 points to make a triangle we need 3 so total no of triangles that can be formed is 14c3.
but 5, 6 and 3 pts lie on one line each.
therefore total no of trianges= 14c3-5c3-6c3-3c3=333

pls correct me if im wrong
11 years agoHelpfull: Yes(77) No(3)

5c1*6c1*3c1 + 5c2*(3c1+6c1) + 6c2*(5c1+3c1) + 3c2*(5c1+6c1)
= 333
11 years agoHelpfull: Yes(13) No(1)
Then what about the actual vertex points?Are they included in 5,6,3??
11 years agoHelpfull: Yes(3) No(1)
yes, vertex points are included in 5,6,3
11 years agoHelpfull: Yes(1) No(0)
YES right is 14c3-5c3-6c3-3c3
11 years agoHelpfull: Yes(1) No(0)
5*9C2+6*8C2+3*11C2
11 years agoHelpfull: Yes(1) No(1)
answer is 233
11 years agoHelpfull: Yes(0) No(1)
yes u r wrong vijayalakshmi ans. is 283
11 years agoHelpfull: Yes(0) No(0)

TCS Other Question

If m+n gives remainder 8 and m-n gives remainder 6 when divided by 12, what is the remainder when mn is divided by 6 ? In how many ways 10 identical pencils can be divided among 4 so that each gets atleast 1 pencil.