two dices are thrown simultaenously what is the probabilty sum of 5 will come before 7...

• for 5- (1,4)(4,1)(2,3)(3,2) ei 4 ways similarly for 7 thr are 6 ways(3,4)(4,3)(6,1)(5,2)(1.6)(2,5)..................out of a total of 10 ways getting a 5 will be in 4/10 ways (its a question from arun sharma)
• 11 years agoHelpfull: Yes(27) No(3)
• we do not have to consider any sum other than 5 or 7 occuring.
  a sum of 5 can be obtained by any of [4+1,3+2,2+3,1+4]
  similarly a sum of 7 can be obtained as [6+1,5+2,2+5,4+3,3+4,1+6]
  as 5 will come before 7 so number of fav. events will be n (e)=4
  and total number of events will be 6+4=10
  therefore probability will be = 4/10=0.4
• 11 years agoHelpfull: Yes(9) No(2)
• 0.4 ans :)
  
• 11 years agoHelpfull: Yes(5) No(4)
• 4/10 ans :
  
  
• 11 years agoHelpfull: Yes(4) No(3)
• ans-- 2/5
  
• 11 years agoHelpfull: Yes(2) No(5)
• sum for 5=4 sets. sum for 7=6 sets. so out of 10 we need problty for sum of 5 only . ansr is 4/10=2/5
• 11 years agoHelpfull: Yes(2) No(1)
• @kunal verma if u have arun sharma softcopy plz send to my mail ksubashmse@gmail.com or plz send the free download pdf link for tht
• 11 years agoHelpfull: Yes(1) No(5)
• is it necesaary to solve arun sharma or uploaded qstn r suffcnt ???pls reply
  
• 11 years agoHelpfull: Yes(0) No(0)