Which of the following straight lines are perpendicular to each other?

2x+y=8

x=4

y=6

2y=x+3

• 2x+y=8 is perpendicular to 2y=x+3 and x=4 is perpendicular to y=6;
  
  break equation in y=mx+c type where m is slope of a line and if product of slope of two lines is -1 then they are perpendicular to each other
• 13 years agoHelpfull: Yes(4) No(0)
• 1st and 4th line are perpendicular to each other in y = mx +c with slope -2 and 1/2 respectively .
  
  and 2nd perpendicular to 3rd as they parallel to y axis and x axis respectively
• 13 years agoHelpfull: Yes(2) No(0)
• 1st with 4th and 2nd with 3rd
• 13 years agoHelpfull: Yes(1) No(0)
• 2x + y = 8........(i) and 2y = x+ 3.....(ii) straight lines are perpendicular to each other.
  from equation (i), y = -2x + 8 , slope m1 = -2
  and from eqn (ii) y = x/2 +3/2 , slope m2 = 1/2
  fro perpendicular m1*m2 = -1
  here we are getting -2*1/2 = -1
  So, (i) and (iv) lines are perpendicular to each other
  
• 13 years agoHelpfull: Yes(1) No(0)
• x=4 is a line parallel to y axis and y=6 is a line parallel to x axis so they both are perpendicular to each other..
  
• 13 years agoHelpfull: Yes(0) No(0)
• first and fourth
• 13 years agoHelpfull: Yes(0) No(0)
• x=4 is a st line parallel to the y axis and y=6 is parallel to the x axis.So they are perpendicular to each other.
• 13 years agoHelpfull: Yes(0) No(0)
• since x=4 is || to y-axis and y=6 is || to x-axis so they are perpendicular to eachother........now we know that y=mx+c
  so from 1st&4th equation's :
  y=-2x+8;
  y=1/2 + 1.5
  comparing both equation's with y=mx+c, we get:
  m1=-2 and m2=1/2
  for two lines to be perpendicular::product of their slopes=-1
  here, m1*m2=-1
  so 1st and 4th lines are perpendicular to each other
• 13 years agoHelpfull: Yes(0) No(0)