The size of a program is N. And the memory occupied by the program is given byM = square root of 100N. If the size of the program is increased by 1% then how much more memory is required now?

• for,size=N
  M=sqrt(100N)
  =10sqrt(N)
  new size=N+(1/100)*N
  =N+.01N
  =1.01N
  new value for M=sqrt(100*(1.01N))
  =10sqrt(1.01N)
  increase in M=10(sqrt(1.01N)-sqrt(N))
  
• 13 years agoHelpfull: Yes(3) No(1)
• it could also be stated as increase in M={sqrt(101N)-sqrt(100N)}
• 13 years agoHelpfull: Yes(3) No(1)
• m=sqrt(100N+1)
  because given M=sqrt(N)
  now size increases by 1%=N+0.01
  now M=sqrt(100(N+0.01))
  =sqrt(100N+1)
• 13 years agoHelpfull: Yes(0) No(2)
• M=sqrt(100N)=10*sqrt(N)
  
  M2=sqrt(100*1.01N)=sqrt(101N)=sqrt(101) * sqrt(N)
  
  M2-M= Sqrt(N) ( Sqrt(101) - 10)= Sqrt(N) (.05)
  = Sqrt(N) / 20
• 13 years agoHelpfull: Yes(0) No(1)
• m=sqrt(100n)
  after increase 1% in n =1.01n
  now
  m=sqrt(100*1.01n)
  m=101/100sqrt(n)=10.1sqrt(n)
  more memory required is=10.1sqrt(n)-10sqrt(n)=0.1sqrt(n) Answer
• 13 years agoHelpfull: Yes(0) No(1)
• Answer is 0.5% bcoz...
  
  
  take n=100 then memory m=sqrt(100n)=sqrt(10000)=100
  
  Increase n by 1% then
  
  n=101 then memory m=sqrt(100n)=sqrt(10100)=100.5
  
  
  then memory will be increased by 0.5%
• 8 years agoHelpfull: Yes(0) No(0)
• 1)m=sqrt(100N)
  2)1m/100=?(Here we are finding the increased one)
  3)Ans:- 0.1sqrt(N)
• 7 years agoHelpfull: Yes(0) No(0)