18 Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is:

• ans is 4 points...
  1 point inside the triangle and 3 outside
• 13 years agoHelpfull: Yes(9) No(1)
• for triangle 3 ex-centers and 1in centers. totally 4 points
• 13 years agoHelpfull: Yes(5) No(0)
• ans will be 4.
• 13 years agoHelpfull: Yes(3) No(0)
• 1...the number of point will be one because there is only one centre of triangle
  .
• 13 years agoHelpfull: Yes(2) No(3)
• 1 is the answer
• 13 years agoHelpfull: Yes(1) No(2)