TCS
Company
Numerical Ability
Percentage
if a man sell 12 mangoes for Rs.10 each,he get a loss of x% and if he sell at Rs. 12 each he makes a profit of x%.find value of x?
Read Solution (Total 9)
-
- ans the sp of 12 mangoes at Rs.10 is 120....and the s.p. at 12 rs each is Rs.144
let CP be x
cp-120/cp=144-cp/cp
therfre cp=132
therfore percent of loss is (12/132)*100=9.09% - 11 years agoHelpfull: Yes(15) No(0)
- if he sell at 10rs each,price of 12=120
if he sell at 12rs each,price of 12=144
and the avg if both 132
so x=(12/132)*100=9.09 - 11 years agoHelpfull: Yes(7) No(1)
- answer is 9.09............
- 11 years agoHelpfull: Yes(6) No(2)
- selling price at a loss of x%=12*10=120
selling price at a profit of x%=12*12=144
2*x=(144-120)
=>x=12
therefore x%=(12*100)/132=9.09%
- 11 years agoHelpfull: Yes(3) No(0)
- 12 mangoes= rs 10 ,loss x %
if 12 mangoes = Rs 12, profit x%
simply the c.p is 11 rupees,
so the ans is 1 rupee loss and profit 1/11 so it is 9.09 % - 11 years agoHelpfull: Yes(2) No(0)
- let cost price = y
((12-y)/y)*100=((y-10)/y)*100
12-y=10-y
22=2y
y=11
x=1 - 11 years agoHelpfull: Yes(1) No(5)
- sp of 12 mangoes=120(in case of loss)
cp-(cp*x/100)=120 i.e; cp(1-x/100)=120...(1)
similarly in case of profit
cp+(cp*x/100)=144 i.e; cp(1+x/100)=144.....(2)
solve both the equation (1)/(2)
x=9.09
- 11 years agoHelpfull: Yes(1) No(0)
- as the profit and loss percent are same,so equate them.....
let the c.p be y,
((12-y)/y*)100=((y-10)/y)*100
so y=11
now loss=c.p-s.p
11-10=1
x=(1/11)*100=9.09 - 11 years agoHelpfull: Yes(0) No(0)
- its 9.090909091 %
- 11 years agoHelpfull: Yes(0) No(0)
TCS Other Question