find sum of sharp angles in 5 pointed star

• answer will be 180
  let an angle of 5 star is a,b,c,d,e
  then (180-a)+(180-b)+(180-c)+(180-d)+(180-e)=720
  now a+b+c+d+e=900-720=>180
• 11 years agoHelpfull: Yes(15) No(1)
• @manoj how 720 will come?
• 11 years agoHelpfull: Yes(8) No(0)
• ANS IS 180
  SUM OF INTERIOR ANGLES = (NUMBER OF SIDES - 2) * 180°
  
  For a 5-sided polygon (pentagon) this is (5-2)*180° = 3*180°=540°
  
  Since all 5 angles of a regular pentagon are equal, each
  interior angle of the regular pentagon is 540%5° = 108°
  Its suppplement is found by subtracting 180°-108°=72°(the 2 angles except the sharp pointer angle)
  so. pointer angle=(180-72-72)=36
  similarly for rest pointed angles
  so, sum of pointed angles=5*36=180
• 11 years agoHelpfull: Yes(4) No(0)
• 360 degree
  
• 11 years agoHelpfull: Yes(2) No(3)
• (2n-8)*90..ans is 180
• 11 years agoHelpfull: Yes(2) No(0)
• 180 degrees
  ie 36 degreee of each sharp angle
• 11 years agoHelpfull: Yes(1) No(1)
• ans=36*5=180
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 360
• 11 years agoHelpfull: Yes(0) No(1)
• answer is 5*35=180.........
• 11 years agoHelpfull: Yes(0) No(9)
• Akash Srivastava.. explain how you got 180 and how did you calculated each 36?
  
• 11 years agoHelpfull: Yes(0) No(0)
• answer would be 540
• 11 years agoHelpfull: Yes(0) No(4)
• sum of angle of polygon that form in between the star is
  (5-2)*180=540 that is a+b+c+d+e
  and let the angle of the star are a1,a2,a3,a4,a5
  so 180-a1=other two angle of tringle
  and those angle are equal to 180-a and 180-b so similarly
  2*180-2(a+b+c+d+e)=180-a1+180-a2+180-a3+180-a4+180-a5
  1800-2*(540)=900-(a1+a2+a3+a4+a5)
  540=a1+a2+a3+a4+a5
  
• 11 years agoHelpfull: Yes(0) No(2)
• @arun check it..... http://mathforum.org/library/drmath/view/57813.html
• 11 years agoHelpfull: Yes(0) No(0)