In a class of 75 students, 44 play cricket ,55 play foot ball each students plays at least one game. what is the probability that a random chosen student from this class plays only cricket.

a .44/75
b .4/15
c. 6/11
d. 11/25

• 44+55=99
  99-75=24 play both
  44-24=20 play only cricket
  p=20/75=4/15
• 10 years agoHelpfull: Yes(57) No(0)
• b)-4/15
  
  (cUf)=99 so (c intrsectn f)=24 => 44-24=20(only cricket)
  p(c)=20/75 i.e. 4/15
  
• 10 years agoHelpfull: Yes(5) No(1)
• 4/15
  total = cricket + football - common_in_both
  75 = 44 + 55 - x
  x = 24
  cricket = 20
  probability = 20/75 = 4/15
• 10 years agoHelpfull: Yes(3) No(0)
• 75-44=31 55-31=24
  totally 24 students play cricket and football. only 20 are play the cricket.
  20/75=4/15
  ans is b.4/15
• 10 years agoHelpfull: Yes(3) No(0)
• 44-x + x + 55-x = 75,
  Therefore,
  x= 24.
  So, No, of persons who play only cricked:- 44-x = 44-24=20.
  
  So, prob= 20/75=4/15 Ans.
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• BY VENN DIAGRAM ANS IS 4/15= PLAYER PLAYED CRICET ONY =20
  TOTAL 75.THEREFOR 20/75=4/15 ANS
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• 20 students play cricket.
  
  Total probability that a student plays cricket is 20/75 = 4/15 Ans.
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• 20/75 ==>4/15
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