3 people to be seated on 3 seats such that none of them sit adjacent to each othe

• 5p3+4p3=54
• 11 years agoHelpfull: Yes(10) No(14)
• Sry the question was typed wrong.....it is 9 seats instead of 3.
• 11 years agoHelpfull: Yes(8) No(0)
• in 9 seats there are even and odd places
  even places:2,4,6,8 i.e,four places so 4p3*3|
  odd places:1,3,5,7,9 i.e,five places so 5p3*3|
  so answer is (4p3*3|)+(5p3*3|)
• 11 years agoHelpfull: Yes(6) No(5)
• bhai kehna kya chahte ho.....
• 11 years agoHelpfull: Yes(3) No(1)
• can any body tell the correct answer
• 11 years agoHelpfull: Yes(3) No(1)
• (9c3-7c1)*3!
• 11 years agoHelpfull: Yes(3) No(0)
• @ Arpit Tantia
  if know answer, plz explain
• 11 years agoHelpfull: Yes(2) No(0)
• 5c3*3!
  4c3*3!
  it is the answer
  
• 11 years agoHelpfull: Yes(2) No(0)
• 9c3-7c1=77
• 11 years agoHelpfull: Yes(1) No(4)
• 5p3+4p3 =60+24=84
• 11 years agoHelpfull: Yes(1) No(2)
• IF SUPPOSE THAT 3 ARE PERTICULAR PEOPLE NOT SITTING ADJACENT TO EACH OTHER,...INSTEAD OF 6 EMPTY SEAT WE CAN SAY THAT WE SAY THAT 6 PERSON TO BE SIT IN !6 WAYS THEN....BETWEEN THEM THERE ARE 7 VACENT PLACE BETWEEN THEM THEREFORE THE 3 PLACE CAN BE SELECTED IN 7C3 AND THE ARRAGED IN !3 WAYS SO ..ANS IS 7C3*!3
  
• 11 years agoHelpfull: Yes(1) No(0)
• Question is wrong !!!
• 11 years agoHelpfull: Yes(1) No(1)
• I am sorry.
  
  They can seat in 2 ways. and answer is correct !!!
  
  A B C -> LET ITS BE THEIR ACTUAL POSITION
  C A B -> ONE ARRANGEMENT
  B C A -> SECOND ARRANGEMENT
  
  So, there are two arrangements :)
• 11 years agoHelpfull: Yes(1) No(0)