SSC Government Jobs Exams Numerical Ability Time and Work

Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did, the work would have been completed in 3 days. To, complete the job alone, A would require how many days?

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concluding from question,
(2x + 1/3y) 3 = (x + y) 5
.
.
.
1x=4y
x=4 and y =1
now find total work, 4+1=5 *5days= 25
A can do in 25/4....6 1/4.
8 years agoHelpfull: Yes(2) No(0)

Let us assume A's efficiency is A & B's is B
then,
1/A+1/B=1/5 --------(i)
since efficiency of A is increased as twice so,
in 2nd case
2/A+1/B=1/3 ------- (ii)

solving (i) & (ii) we get
A= 15/2 = 7.5 days alone needed by A to complete work
7 years agoHelpfull: Yes(2) No(0)
in this que. it is not mentioned that b works at 1/3 of his efficiency
7 years agoHelpfull: Yes(0) No(0)

SSC Other Question

Three persons undertake to complete a piece of work for Rs.1200. The first person can complete the work in 8 days, second person in 12 days and third person in 16 days. They complete the work with the help of a fourth person in 3 days. What does the fourth person get? A can do a piece of work in 20days and B in 30 days. They worked together for 7 days and then both leave the work. Then C alone finishes the remaining work in 10 days. In how many days will C finish the full work?