when a number divided by 357 gives remainder 5.what will be remainder if the same no is divided by 17?

• use the simple formula
  dividend =divisor*quotient +rem
  let the number be n,
  n=357*q1+5
  similarly for
  n=17*q2 + R {R is the remainder ,which is to be founded }
  on equating we get
  17*q2 + R = 357*q1 +5
  therefore R = 17*21*q1 +5 -17 *q2
  = 17(21*q1 -q2) +5
  so Remainder = 5
• 10 years agoHelpfull: Yes(25) No(1)
• The remainder will be 5 because 357 is divisible by 17.
• 10 years agoHelpfull: Yes(14) No(4)
• the number which when divided by 357 and gives remainder 5 will be like (357xX)+5 or (21x17xX)+5....this number when divided by 17 will also generate remainder equal to 5...bcoz the first part of given numbr i,e. (21x17xX) is divisible by 17...
• 10 years agoHelpfull: Yes(9) No(0)
• let the no. is x
  so, 357k+5=n
  therefore, (17*18)k+17-12=n
  so ans will be 12.
• 10 years agoHelpfull: Yes(3) No(9)
• ans will be 5 because 357 is divisible by 17.
  
• 10 years agoHelpfull: Yes(2) No(0)
• ans = because 357 is divisible by 17.so 5
• 10 years agoHelpfull: Yes(1) No(0)
• IF THE NUMBER GIVES A REMAINDER 5,THEN THE NUMBER CAN BE 357+5=362,
  NOW,362/17 WE WILL GET REMAINDER 5.
  SO ANS:5
• 10 years agoHelpfull: Yes(1) No(1)
• 5
  as 357 is divisible by 17
• 10 years agoHelpfull: Yes(1) No(0)
• Remainder is 5.
  
• 10 years agoHelpfull: Yes(1) No(0)
• sorry ans will be 5.
• 10 years agoHelpfull: Yes(0) No(2)
• If a num gives a rem of 5 when divided by 357 then it is of form 357 * X + 5. Now when the num is divided by 17 then (357 * X + 5)/17. 357 will get divided by 17. So the remainder will be 0+5=5.
• 10 years agoHelpfull: Yes(0) No(0)