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Numerical Ability
Arithmetic
f(x)=3x^4 + 5x^2 + 3x + 1
f(-3)=3 then find f(3)
Read Solution (Total 6)
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- as we have x with even powers no change in -3 and 3
and f(-3)=3
f(3)=f(-3)+6x=3+6*3=21
- 11 years agoHelpfull: Yes(17) No(19)
- it is 21.
[f(-3)=3]=[3(-3)^4 + 5(-3)^2 +1] + 3(-3)
[3(-3)^4 + 5(-3)^2 + 1]= 3+9=12
f(3)=[3(3)^4 + 5(3)^2 +1] +3(3)= 12 + 9= 21 - 11 years agoHelpfull: Yes(16) No(2)
- 3*3^4+5*3^2+3*3+1=243+45+9+1=298
- 11 years agoHelpfull: Yes(13) No(8)
- f(3)=f(-3)+ 2*3*x= 3+2*3*3=21
- 11 years agoHelpfull: Yes(6) No(0)
- f(-3) is coming out to be 280 and its given f(-3)=3. :/
- 11 years agoHelpfull: Yes(2) No(2)
- Is 380 correct answer ???
- 11 years agoHelpfull: Yes(0) No(0)
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