Two workers one young and one old live together and work in the same office It takes 20 mins and

@ dheeraz...i think the old speed should be x/30 and young speed will be x/20...then after solving the equation t comes out to be 10 mins...so they meet at 10:15 am
11 years agoHelpfull: Yes(17) No(2)

relative speed=3x-2x=x
distance cover by old man in 5min=x/6
t=x/6x=1*60/6min=10min
11 years agoHelpfull: Yes(7) No(7)
let he distance be 60 m .
old's speed = 2 m/m,
young's speed = 3 m/m,
distance covered by old in 5 minutes = 10 meters,
time taken by young to cover same distance with relative speed (3-2)=2 m/m
time = 10/1=10 minutes. So, he will catch old at 10:15 A.M.
11 years agoHelpfull: Yes(7) No(1)
let x be the total distance
old speed=x/20 young speed=x/30

they meet at same distance y
d=speed/time

(x/20)/t=(x/30)/t+5
t=15min
so they meet at 10.20am
11 years agoHelpfull: Yes(5) No(9)
hello sorry it is at 10.15 but procedure is correct
11 years agoHelpfull: Yes(4) No(1)
dheeraj,actually it will be 10.15 am
11 years agoHelpfull: Yes(2) No(1)
young man travel 1.5 times faster than old man.
so....
they will meet at 10:15am..
11 years agoHelpfull: Yes(2) No(1)
Let the distance b/w two points be = 30
so, in 15 mins old man will cover 15 m hence 1m/min.
and young man in 10 min will cover 15m = 1.5m/min.
there fore at 10:15 they will catch up.
11 years agoHelpfull: Yes(2) No(0)
let x be the total distance
old speed=x/20 young speed=x/30

they meet at same distance y
d=speed/time

(x/20)/t=(x/30)/t+5
t=15min
so they meet at 10.15am
11 years agoHelpfull: Yes(2) No(0)
10:15 soo simple ques tcs me ye ni aayga guyss soo dnt wry abt sol.
11 years agoHelpfull: Yes(1) No(4)

Two workers one young and one old live together and work in the same office.It takes 20 mins and 30 mins to walk to office respectively.When will the young man catch up with
the old man,if the old man starts at 10 am and young man starts at 10:05 am?

minutes an