[n^1/3]=5.how many values are exist for n?

• ans will be 91.
  explanation:
  n^1/3 can range from 5.0 to 5.9 then the expression [n^1/3]=5..i.e greatest integer concept.
  so now, we know:
  5^3=125=>n [125^1/3]=[5]=5
  6^3=216=>n [216^1/3]=[6]=6
  so the value of n can range from [125,215] because if n=216 [n^1/3] will be 6.
  hence total values for n=215-125+1=91 //+1 for including both boundary values 125 and 216.
  
  
• 11 years agoHelpfull: Yes(27) No(3)
• hi vk take [ ] this as window for which there are number of values are available. since 5^3 is 125 and 6^3 is 216 so in between them 90 values are possible.
• 11 years agoHelpfull: Yes(5) No(2)
• options-
  90
  91
  1
  3
• 11 years agoHelpfull: Yes(3) No(1)
• [n^1/3]=5 as we know 125^1/3 =5 and 216^1/3= 6.....
  so to satisfy above eqation we can take values of n from 125 to 215 both inclusive..[n] where n is greatest integer less than or equal to n.so total values psbl is 125-215+1=91..
• 11 years agoHelpfull: Yes(2) No(0)
• only one value for n=125
  n^1/3=5
  (n^1/3)^3=(5)^3
  n=125
• 11 years agoHelpfull: Yes(1) No(5)
• explain me clearly,they have given that n^1/3 = 5 then how it lies between 5 and 6..no meaning
  
• 11 years agoHelpfull: Yes(0) No(1)
• 
  only 1 value will satisfy for n^1/3=5, ie- n=125;
  n^1/3=5
  (n^1/3)^3=(5)^3 // will find ^3 for equation
  n=125
• 11 years agoHelpfull: Yes(0) No(2)