excluding stopage average speed of bus is 54km/hr,including stoppage 45km/hr..for how many min bus stop in hour.

• 54-45=9km less covered...so ans = 9/54=1/6*60= 10 mins
• 11 years agoHelpfull: Yes(22) No(0)
• without stoppage speed=54km/hr
  with stoppage speed =45km/hr
  difference=54-45=9
  since if 54km in 60 min
  so 9km in 9*60/54=10 min.
  ans is 10 min.
• 11 years agoHelpfull: Yes(21) No(0)
• Excluding stoppages, X = 54 kmph
  Including stoppages, Y = 45 kmph
  By including stoppages, bus will cover 9km less (54km-45km = 9km)
  i.e., Difference, Z = 9km
  
  Time taken to cover that 9km(bus stops per hour(60 minutes))
  = Z/X(60 minutes)
  = 9/54(60)
  = 1/6(60)
  = 10 minutes.
  
  So, the bus would have taken 10 min to stop in an hour.
• 11 years agoHelpfull: Yes(5) No(0)
• rest time=(difference in speed)/(speed without stoppage)
  =>(54-45)/54
  =>1/6 hr
  =>60*(1/6)min
  =>10 min/hr
• 11 years agoHelpfull: Yes(5) No(0)
• 10 min.
  Due to stoppage,the bus covers (54-45)=9km less
  so,time taken to cover 9km=((9/54)*60)min
  =10 min
• 11 years agoHelpfull: Yes(3) No(0)