In the adjoining figure, ABCD and EFGH are squares of side 1 unit such that they intersect each other such that diagonal CE=1/2. Total area covered by the squares is:
a) Cannot be determined
b) 1/2
c) 11/8
d) 15/8

• 15/8
  
  Diagonal d = 1/2
  d = a*sqrt(2), where a is the side
  ===> a = 1/(2*sqrt(2)) units
  
  Therefore area of overlapping portion of 2 squares = a^2
  = 1/8 square units
  
  Area of the 2 squares = 1^2 + 1^2
  = 2 square units
  
  Subtracting the overlapping portion, area covered by the 2 squares
  = 2 - 1/8
  =15/8 square units
  
• 10 years agoHelpfull: Yes(1) No(0)