65) Which year has the same calendar as 2007?
a) 2011
b) 2012
c) 2014
d) 2015

• 2007+11,or-6 i.e. 2018 and 2001. SO, none of these.
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• ANS is 2018. none of these
  
  the sum of odd days will be multiples of 7(which makes exact week)
  for a regular year we wil be having 365/7 which gives remainder 1 will be having 1 odd day
  and for leap years we will be havin 2 odd days
  So For every ordinary year number of odd days = 1 odd day
  
  For leap year number of odd days = 2 odd days.
  
  If the odd days sum=7 implies odd days=0 then again loop starts from 1,2,3,4,..7 .
  2008,2012,2016 are clearly leap years,
  
  therefore
  2007=1 odd day,
  2008=2 (SUM=3),
  2009=1 (SUM=4),
  2010=1 (SUM=5),
  2011=1 (SUM=6),
  2012=2 odd days (SUM=8)
  [HERE OBSERVE THAT SUM OF ODD DAYS EXCEEDING THE VALUE 7 THEREFORE CONTINUE ADDING THE ODD DAYS TILL WE GET A NUMBER WHICH IS DIVISIBLE BY 7],
  
  2013=1 (SUM=9),
  2014=1 (SUM=10),
  2015=1 (SUM=11),
  2016 = 2 odd days (SUM=13),
  
  2017=1 (SUM=14)
  upto 2017 SUM OF ODD DAYS = 14 divisible by 7 implies next year i.e.,2018 will have same calender as 2007 .
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