From the top of a building 60 metres high the angles of depression of the top and bottom of a tower are 30° and 60° respectively. The height of the tower is,
option
(A) 40m
(B) 30m
(C) 20m
(D) 50m
(E) 23m

• as given,
  From the top of a building 60 metres high the angles of depression of the top and bottom of a tower are 30° and
  60° respectively,
  hence,
  applying tan 60 = p/b =60/base i.e, base = 60/tan 60,
  again,
  tan 30 = p/b = p/(60/tan 60)
  hence, p=20 meters
  so,The height of the tower = (60-20)meters
  = 40 meters
  
  
• 10 years agoHelpfull: Yes(20) No(2)
• answer is 40 only..
• 10 years agoHelpfull: Yes(2) No(1)
• [a] 40m
  60/b=tan(60)
  b=20(sqrt3)
  now p1/20(sqrt3)=tan(30)
  so p1=20
  hieght of tower is 60 -20= 40m
• 10 years agoHelpfull: Yes(0) No(0)
• 40 is ans......
• 8 years agoHelpfull: Yes(0) No(0)