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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first day but slides down 2 feet on the second. It climbs 4 feet on the third day and slides down again 2 feet on the fourth day. If this pattern continues, how many days will it take the snail to reach the top of the wall?
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- A snail climbing a 20 feet high wall, climbs up 4 feet on the first day but slides down 2 feet on the second and so on second day he climb only 2 feet and then same procedure go on consecutive days
in 2 days he climb up 2 feet
so in 16 day he will climb 16 feet,
but on 17th day he will climb 4 feet ,so he will get the destination,so snail will 17 days take the snail to reach the top of the wall
- 11 years agoHelpfull: Yes(58) No(0)
- 17th day it will on the top of the wall.
but also slide down 2 feet in 18th day - 11 years agoHelpfull: Yes(6) No(3)
- In every 2 days snail climb up 2 feet (4 feet up and 2 feet down)
if it reach 16 feet with many up and down it will be 16th day
now in 17th day it climb up 4 feet which is equal to the height of the wall. - 11 years agoHelpfull: Yes(4) No(1)
- 17....
- 11 years agoHelpfull: Yes(2) No(3)
- 17 days
as on 16th day it will climb upto 16 feet and on the next day it will be on the top of wall.....without sliding down - 11 years agoHelpfull: Yes(1) No(0)
- plz explain procedure
- 11 years agoHelpfull: Yes(0) No(4)
- It will take 17 days to climb the top of the wall !!!
- 11 years agoHelpfull: Yes(0) No(0)
- answer is 17
- 5 years agoHelpfull: Yes(0) No(0)
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