from 8 digit numbers from 1,2,3,4,5 with repetation is allowed divisible by 4

• Since, repetition is allowed
  no. is divisible by 4 if the no. formed by last two digits is divisible by 4.
  so last 2 digits must be
  12
  32
  52
  24
  44
  Remaining 1st SIX DIGITS can be arranged in 5^6 Ways.
  therefore answer is 5^6+5^6+5^6+5^6+5^6 = 78125
• 11 years agoHelpfull: Yes(24) No(6)
• ans is 5^7
• 11 years agoHelpfull: Yes(13) No(0)
• 78125
  for last digit 12=5^6(15625)
  ............. 24=15625
  .............. 32=15625
  .............. 44=15625
  ............. 48=15625
  5*15625=78125
• 11 years agoHelpfull: Yes(10) No(3)
• last two digit 12 total no=5*5*5*5*5=5^5
  last two digit 24 total no=5*5*5*5*5=5^5
  last two digit 32 ..................=5^5
  last two digit 44 ..................=5^5
  last two digit 52 ..................=5^5
  
  ans =5*5^5
• 11 years agoHelpfull: Yes(3) No(3)
• 78125 s the right answer
• 11 years agoHelpfull: Yes(3) No(1)
• Total no form by 8 digit 5^8=390625
  now, Total no of last two digit with 12 is 5^6= 15625
  Total no of last two digit with 24 is 5^6= 15625
  Total no of last two digit with 32 is 5^6= 15625
  Total no of last two digit with 44 is 5^6= 15625
  Total no of last two digit with 52 is 5^6= 15625
  
  so the ans= 390625-(5*15625)=312500
• 11 years agoHelpfull: Yes(2) No(5)
• 5*5*5*5*5*5*5=78125
• 11 years agoHelpfull: Yes(2) No(2)
• sorry
  in my soln in place of 5*5*5*5*5=5^5 ,there should be 5*5*5*5*5*5=5^6
• 11 years agoHelpfull: Yes(1) No(2)
• Total possible last two digits
  12
  32
  52
  24
  44
  
  remaining 6 places can be filled in 5^6 ways so total = 5^7
  => 78125 ways.
• 11 years agoHelpfull: Yes(1) No(0)
• it is 5^7 = 78125... not 5^6
• 11 years agoHelpfull: Yes(0) No(0)
• there are for conditions which are divisible by 4 i.e
  12
  24
  32
  52
  44
  hence unit digit can be selected in two ways and rest 7 digit in 5^7 ways.
  so total ways=2*5^7
• 11 years agoHelpfull: Yes(0) No(0)
• 1)v can place 7 position as v wish but last digit should be 4---this permutaion is 7!= 5040
  2)last two digits can be 12,24,32,44,52 so here last two digits are fixed permutation is 6!*5=3600.
  3) so total numbers that can be formed by 12345 are 5040+3600=8640.
  
  
• 11 years agoHelpfull: Yes(0) No(0)