find the last 3 digits of 8 88 888 8888 till 22 terms asked in tcs svits

22*8 = 176 last digit is 6 nd carry 17
21*8 = 168 now 168 + 17 = 185 2nd last digit is 5 nd carry 18
20*8 = 160 now 160 + 18 178 3rd digit from last is 8

so last 3 digit is 856
11 years agoHelpfull: Yes(46) No(0)
1st term 008
2nd term 088
last 3 digits 888*20=856
final last two digits=8+88+856=952
11 years agoHelpfull: Yes(4) No(26)
8+88+888 till 22 terms mean..
at unit's 22X8= 17(6) select 6 and 17 carry over at 10's.
at ten's 22X8= 176+17 carry= 18(3). select 3 and 18 carry at 100's.
at 100's 22X8=176+ 18 of carry = 19(4). 4 selected.
therefore last 3 digit's are.. 436

436.
11 years agoHelpfull: Yes(1) No(9)
888*20 +88 +8 =17856,

so, last three digits are 856.
11 years agoHelpfull: Yes(1) No(0)
(8 x 22) = 176
(8 x 21)+ 17 = 205
(8 x 20)+ 20 = 180
so the last three digits are 056
10 years agoHelpfull: Yes(1) No(0)
answer is 856
9 years agoHelpfull: Yes(0) No(0)
last term 22
22*8=176
21*8=168+17=185
20*8=160+18=178
take last digit of all and arrenge down to top
856 Answer
9 years agoHelpfull: Yes(0) No(0)
8(1+11+111+1111...........................................1111111(22times)
last 3 digits will be 8*32=256.
Hence ans is 256
9 years agoHelpfull: Yes(0) No(0)

find the last 3 digits of 8 + 88 +888 +8888 ..... till 22 terms ... asked in tcs svits